Lesson : : transformation

To solve the quadratic equation:

$$x^2 – 5x + 5 = 0$$

We use the quadratic formula:

$$x = \frac{-b \pm \sqrt{b^2 – 4ac}}{2a}$$

Here, $a = 1$, $b = -5$, $c = 5$

$$x = \frac{-(-5) \pm \sqrt{(-5)^2 – 4(1)(5)}}{2(1)} = \frac{5 \pm \sqrt{25 – 20}}{2} = \frac{5 \pm \sqrt{5}}{2}$$

Final Answer:

$$x=\frac{5\pm \sqrt{5}}{2}$$

  Translation